Bucktown, Indiana
Appearance
Bucktown, Indiana | |
---|---|
![]() Sullivan County's location in Indiana | |
Location in Sullivan County, Indiana | |
Coordinates: 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W | |
Country | United States |
State | Indiana |
County | Sullivan |
Township | Jefferson |
Elevation | 594 ft (181 m) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 47838 |
Area code(s) | 812, 930 |
GNIS feature ID | 431756 |
Bucktown is an unincorporated community in Jefferson Township, Sullivan County, in the U.S. state of Indiana.[2]
The community is part of the Terre Haute Metropolitan Statistical Area.
Geography
[edit]Bucktown is located at 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W.
References
[edit]- ^ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved August 29, 2016.
- ^ "Bucktown, Indiana". Geographic Names Information System. United States Geological Survey. Retrieved August 5, 2017.