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1998 Paris Open

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1998 Paris Open
Date2–9 November
Edition26th
CategoryATP Super 9
Draw48S / 24D
Prize money$2,300,000
SurfaceCarpet / indoor
LocationParis, France
VenuePalais omnisports de Paris-Bercy
Champions
Singles
United Kingdom Greg Rusedski[1]
Doubles
India Mahesh Bhupathi / India Leander Paes[2]
← 1997 · Paris Masters · 1999 →

The 1998 Paris Open was a men's tennis tournament played on indoor carpet courts. It was the 26th edition of the Paris Masters, and is part of the ATP Super 9 of the 1998 ATP Tour. It took place at the Palais omnisports de Paris-Bercy in Paris, France, from 2 November through 9 November 1998. Thirteenth-seeded Greg Rusedski won the singles title.

Finals

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Singles

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United Kingdom Greg Rusedski defeated United States Pete Sampras 6–4, 7–6(7–4), 6–3

  • It was Greg Rusedski's 2nd singles title of the year and his 7th overall. It was his 1st Masters title of the year, and overall.

Doubles

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India Mahesh Bhupathi / India Leander Paes defeated Netherlands Jacco Eltingh / Netherlands Paul Haarhuis 6–4, 6–2

References

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  1. ^ "1998 Paris – Singles draw". Association of Tennis Professionals (ATP).
  2. ^ "1998 Paris – Doubles draw". Association of Tennis Professionals (ATP).
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