1865 Iowa gubernatorial election
Appearance
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![]() County results Stone: 50-60% 60-70% 70-80% 80-90% 90-100% Benton: 50-60% 60-70% 70-80% 80-90% No Data/Votes: | |||||||||||||||||
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Elections in Iowa |
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The 1865 Iowa gubernatorial election was held on 10 October 1865 in order to elect the Governor of Iowa. Incumbent Republican Governor William M. Stone was re-elected against Democratic nominee Thomas H. Benton.[1]
General election
[edit]On election day, 10 October 1865, incumbent Republican Governor William M. Stone won re-election by a margin of 16,371 votes against his opponent Democratic nominee Thomas H. Benton, thereby holding Republican control over the office of Governor. Stone was sworn in for his second term on 16 January 1866.[2]
Results
[edit]Party | Candidate | Votes | % | |
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Republican | William M. Stone | 70,461 | 56.41 | |
Democratic | Thomas H. Benton | 54,090 | 43.31 | |
Scattering | 353 | 0.28 | ||
Total votes | 124,904 | 100.00 | ||
Republican hold |
References
[edit]- ^ "William Milo Stone". National Governors Association. Retrieved 28 November 2023.
- ^ "IA Governor". ourcampaigns.com. 25 July 2005. Retrieved 28 November 2023.
- ^ Iowa General Assembly. Journal of the House of Representatives. 1866 sess., 3, accessed 28 November 2023