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1916 Iowa gubernatorial election

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1916 Iowa gubernatorial election

← 1914 November 7, 1916 1918 →
 
Nominee William L. Harding Edwin T. Meredith
Party Republican Democratic
Popular vote 313,586 186,832
Percentage 61.03% 36.36%

County results
Harding:      40-50%      50-60%      60-70%      70-80%
Meredith:      50-60%

Governor before election

George W. Clarke
Republican

Elected Governor

William L. Harding
Republican

The 1916 Iowa gubernatorial election was held on November 7, 1916. Republican nominee William L. Harding defeated Democratic nominee Edwin T. Meredith with 61.03% of the vote.

General election

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Candidates

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Major party candidates

  • William L. Harding, Republican
  • Edwin T. Meredith, Democratic

Other candidates

  • John W. Bennett, Socialist
  • Oren D. Ellett, Prohibition
  • Stephen H. Bashor, Progressive
  • Arthur S. Dowler, Socialist Labor

Results

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1916 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican William L. Harding 313,586 61.03%
Democratic Edwin T. Meredith 186,832 36.36%
Socialist John W. Bennett 8,200 1.60%
Prohibition Oren D. Ellett 2,880 0.56%
Progressive Stephen H. Bashor 2,035 0.40%
Socialist Labor Arthur S. Dowler 315 0.06%
Majority 126,754
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 2, 2020.